Justin had $130 more than Xavier at first. Justin gave $20 to Xavier. As a result, Xavier has
25 as much money as Justin. How much money had each of them at first?
- Justin
- Xavier
| |
Justin |
Xavier |
More |
| Before |
5 u + $20 |
2 u - $20 |
$130 |
| Change |
- $20 |
+ $20 |
|
| After |
5 u |
2 u |
|
(a)
Justin had $130 more than Xavier at first. If Xavier received another $130, Justin and Xavier would have the same amount at first.
5 u + 20 = 2 u - 20 + 130
5 u + 20 = 2 u + 110
5 u - 2 u = 110 - 20
3 u = 90
1 u = 90 ÷ 3 = 30
Amount that Justin had at first
= 5 u + 20
= 5 x 30 + 20
= 150 + 20
= $170
(b)
Amount that Xavier had at first
= 2 u - 20
= 2 x 30 - 20
= 60 - 20
= $40
Answer(s): (a) $170; (b) $40
