One eatery bought 141 kg of beef and pork.
12 of the beef and
35 of the pork were sold. The amount of pork sold was 12 kg more than the amount of beef sold.
- How much pork did the eatery buy?
- How much beef did the eatery buy?
|
Beef |
Pork |
Total |
Before |
2x3 = 6 u |
5 u |
+ 20 |
141 |
Change |
- 1x3 = - 3 u |
- 3 u |
- 12 |
|
After |
1x3 = 3 u |
2 u |
+ 8 |
|
(a)
12 ÷ 3 x 5 = 20
12 ÷ 3 x 2 = 8
Total mass of beef and pork bought
= 6 u + 5 u + 20
= 11 u + 20
11 u + 20 = 141
11 u = 141 - 20
11 u = 121
1 u = 121 ÷ 11 = 11
Mass of pork bought
= 5 u + 20
= 5 x 11 + 20
= 55 + 20
= 75 kg
(b)
Mass of beef bought
= 6 u
= 6 x 11
= 66 kg
Answer(s): (a) 75 kg; (b) 66 kg