One eatery bought 108 kg of beef and pork.
13 of the beef and
58 of the pork were sold. The amount of pork sold was 10 kg more than the amount of beef sold.
- How much pork did the eatery buy?
- How much beef did the eatery buy?
|
Beef |
Pork |
Total |
Before |
3x5 = 15 u |
8 u |
+ 16 |
108 |
Change |
- 1x5 = - 5 u |
- 5 u |
- 10 |
|
After |
2x5 = 10 u |
3 u |
+ 6 |
|
(a)
10 ÷ 5 x 8 = 16
10 ÷ 5 x 3 = 6
Total mass of beef and pork bought
= 15 u + 8 u + 16
= 23 u + 16
23 u + 16 = 108
23 u = 108 - 16
23 u = 92
1 u = 92 ÷ 23 = 4
Mass of pork bought
= 8 u + 16
= 8 x 4 + 16
= 32 + 16
= 48 kg
(b)
Mass of beef bought
= 15 u
= 15 x 4
= 60 kg
Answer(s): (a) 48 kg; (b) 60 kg