Mark, Albert and Ian bought some macarons. After Mark ate ³₅ of his macarons, Albert ate ²₃ of his macarons and Ian ate 4 macarons, each of them had the same number of macarons left. Mark had 10 less macarons than Albert at first.

1. How many macarons did Mark have at first?
2. How many macarons did the 3 of them buy altogether? 

	Mark	Albert	Ian
Before	5 u	3x2 = 6 u	2 u + 4
Change	- 3 u	- 2x2 = - 4 u	- 4
After	2 u	1x2 = 2 u	2 u

(a)
The number of macarons that Mark and Albert each had in the end is the same. Make the number of macarons that Mark and Albert each had in the end the same.  LCM of 2 and 1 is 2.

Number of macarons that Mark had less than Albert at first
= 6 u - 5 u
= 1 u

1 u = 10

1 u = 10 ÷ 1 = 10

Number of macarons that Mark had at first
= 5 u
= 5 x 10
= 50 

(b)
Total number of macarons that the 3 of them bought
= 5 u + 6 u + 2 u + 4
= 13 u + 4
= 13 x 10 + 4
= 130 + 4
= 134

Answer(s): (a) 50; (b) 134