Cole and Mark had 68 tarts altogether. After Cole ate
13 of his tarts and Mark ate 5 tarts, the number of tarts Mark had left was twice the number of tarts Cole had left. How many more tarts did Mark have than Cole at first?
| |
Cole |
Mark |
Total |
| Before |
3 u |
4 u + 5 |
68 |
| Change |
- 1 u |
- 5 |
|
| After |
2 u |
|
|
Comparing Cole and
Mark in the end |
1x2 =
2 u |
2x2 =
4 u |
|
The number of tarts that Cole had in the end is the same. Make the number of tarts that Cole had in the end the same. LCM of 2 and 1 is 2.
Total number of tarts at first
= 3 u + 4 u + 5
= 7 u + 5
7 u + 5 = 68
7 u = 68 - 5
7 u = 63
1 u = 63 ÷ 7 = 9
Number of tarts that Cole had at first
= 3 u
= 3 x 9
= 27
Number of tarts that Mark had at first
= 68 - 27
= 41
Number of tarts that Mark had more than Cole at first
= 41 - 27
= 14
Answer(s): 14
