Riordan and Albert had $225 altogether. After Riordan spent
13 of his money and Albert spent
23 of his money, Riordan was left with thrice as much money as Albert. How much money did Albert have at first?
| |
Riordan |
Albert |
Total |
| Before |
3x3 =
9 u |
3x2 =
6 u |
$225 |
| Change |
- 1x3 =
- 3 u |
- 2x2 =
- 4 u |
|
| After |
2x3 =
6 u |
1x2 =
2 u |
|
Comparing Riordan
and Albert in the end |
3x2 =
6 u |
1x2 =
2 u |
|
The amount that Riordan had in the end is repeated. Make the amount that Riordan had in the end the same. LCM of 2 and 3 is 6.
Total amount that Riordan and Albert had at first
= 9 u + 6 u
= 15 u
15 u = 225
1 u = 225 ÷ 15 = 15
Amount that Albert had at first
= 6 u
= 6 x 15
= $90
Answer(s): $90
