In a kiosk, some water guns and frisbees were on sale.
111 of the items were water guns.
23 of the water guns and 565 frisbees were sold. There were
112 of the items left in the kiosk. How many water guns and frisbees were there in the kiosk at first?
| |
Water guns |
Frisbees |
Total |
Comparing water guns
and frisbees at first |
1x12 =
12 u |
10x12 =
120 u |
11x12 =
132 u |
| Before |
3x4 =
12 u |
|
12x11 =
132 u |
| Change |
- 2x4 =
- 8 u |
- 565
|
- 11x11 =
- 121 u |
| After |
1x4 =
4 u |
7 u |
1x11 =
11 u |
The total number of toys at first is repeated. Make the total number of toys at first the same. LCM of 11 and 12 is 132.
The number of water guns at first is repeated. Make the number of water guns the same. LCM of 12 and 3 is 12.
Number of frisbees left
= 11 u - 4 u
= 7 u
Number of frisbees sold
= 120 u - 7 u
= 113 u
113 u = 565
1 u = 565 ÷ 113 = 5
Number of water guns and frisbees at first
= 132 u
= 132 x 5
= 660
Answer(s): 660
