Yoko, Xuan and Tiffany had sweets in the ratio of 9 : 2 : 1. After Yoko gave 35 sweets to Xuan and Tiffany, the three of them had the same number of sweets. Find the total number of sweets the children had.
| |
Yoko |
Xuan |
Tiffany |
Total |
| Before |
9 u |
2 u |
1 u |
12 u |
| Change |
- 35 |
+ 35 |
|
| After |
4 u |
4 u |
4 u |
12 u |
Total number of sweets
= 9 u + 2 u + 1 u
= 12 u
Number of sweets that each had in the end
= 12 u ÷ 3
= 4 u
Number of sweets that Yoko gave to Xuan and Tiffany
= 9 u - 4 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Total number of sweets
= 12 u
= 12 x 7
= 84
Answer(s): 84
