Two identical pails L and M contained some water. Pail L was ¹₉ filled and Pail M was ¹₁₀ filled. The ratio of the total mass of Pail L and the water in it to the total mass of Pail M and the water in it was 13 : 12. The total mass of the two pails and the water they contained was 2750 g. What is the mass of an empty pail?
Mass of Pail L and the water inside = 13 u
Mass of Pail M and the water inside = 12 u

Total mass of the two pails and the water inside them
= 13 u + 12 u
= 25 u

25 u = 2750

1 u = 2750 ÷ 25 = 110

Mass of Pail L and the water in it more than mass of Pail M and the water in it 
= 13 u - 12 u
= 1 u

Fraction of the water that Pail L had more than Pail M 
= ¹₉ - ¹₁₀
= ¹⁰₉₀ - ⁹₉₀
= ¹₉₀ 

¹₉₀ of the water capacity → 1 u
⁹₉₀ of the water capacity → 9 x 1 u = 9 u

Mass of an empty pail
= 12 u - 9 u
= 3 u
= 3 x 110
= 330 g

Answer(s): 330 g