There was an equal number of silver and blue balls in a box at first. After 24 blue balls were taken out and 42 silver balls were added into the box, there was
17 as many blue balls as silver balls. Find the number of blue balls in the box at first.
| |
Silver balls |
Blue balls |
| Before |
7 u - 42 |
1 u + 24 |
| Change |
+ 42 |
- 24 |
| After |
7 u |
1 u |
The number of silver and blue balls in the box is the same at first.
7 u - 42 = 1 u + 24
7 u - 1 u = 24 + 42
6 u = 66
1 u = 66 ÷ 6 = 11
Number of blue balls at first
= 1 u + 24
= 11 + 24
= 35
Answer(s)35
