A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.90 |
Every 400 m thereafter or less |
$0.90 |
Xuan paid a taxi fare of $11.90. What was the greatest distance that Xuan could have travelled in the taxi? Give your answer in km.
Amount that Xuan paid for the additional distance
= 11.90 - 2.90
= $9
Number of sets of $0.90 that Xuan paid for the edditional distance
= 9 ÷ 0.90
= 10
Total additional distance that Xuan could have travelled in the taxi
= 10 x 400
= 4000 m
1000 m = 1 km
4000 m = 4000 ÷ 1000 = 4 km
Greatest distance that Xuan could have travelled in the taxi
= 1 + 4
= 5 km
Answer(s): 5 km