The figure shows the amount of water in two rectangular tanks, S and T, at first. Pierre poured
13 of the water from S into T to fill it to the top, without overflowing.
- How much water was there in Tank S at first?
- Pierre then poured all the water from Tank T into Tank S. 704 cm3 of water overflowed from Tank S. What was the height of Tank S?
(a)
Volume of water to fill Tank T
= 16 x 14 x 16
= 3584 cm
3
13 of volume of water in Tank S at first = 3584 cm
3
33 of volume of water in Tank S at first = 3 x 3584 = 10752 cm
3 Volume of water in Tank S at first = 10752 cm
3 Volume of water in Tank T at first
= 16 x 14 x 18
= 4032 cm
3 Total volume of water in Tank S and Tank T
= 10752 + 4032
= 14784 cm
3 Final volume of water in Tank S after 704 cm
3 of water overflowed
= 14784 - 704
= 14080 cm
3 Base area of Tank S
= 20 x 16
= 320 cm
2 Height of Tank S
= 14080 ÷ 320
= 44 cm
Answer(s): (a) 10752 cm
2 ; (b) 44 cm