PSLE There was a total of 26292 cm
3 of water in rectangular tanks D and E at first. The height of the water level in tank E was 2 cm above that of tank D.
- Find the height of the water level in tank D.
- Hazel poured 4440 cm3 of water out of tank E. Tank E was then half filled with water. What was the height of tank E?
(a)
Volume of water in Tank E with a height of 2 cm
= 37 x 30 x 2
= 2220 cm
3 Volume of water in both tanks excluding the water that is 2 cm above that of Tank D
= 26292 - 2220
= 24072 cm
3 Base area of Tank D
= 32 x 28
= 896 cm
2 Base area of Tank E
= 37 x 30
= 1110 cm
2 Combined base areas of both tanks
= 896 + 1110
= 2006 cm
2 Height of water in Tank D
= 24072 ÷ 2006
= 12 cm
(b)
Decrease in the height of Tank E after some water was poured out
= 4440 ÷ 1110
= 4 cm
Original height of water before some was poured out
= 12 + 2
= 14 cm
Height of water after some was poured out
= 14 - 4
= 10 cm
Height of Tank D
= 2 x 10
= 20 cm
Answer(s): (a) 12 cm; (b) 20 cm