At a stall, the ratio of limes to papayas was 3 : 10. After Hazel bought two-fifths of the papayas, there was a total of 72 limes and papayas left at the stall. How many fruits were there at first?
| |
Limes |
Papayas |
Total |
Comparing limes
and papayas at first |
3x1 =
3 u |
10x1 =
10 u |
13 u |
Before |
|
5x2 =
10 u |
|
Change |
|
- 2x2 =
- 4 u |
|
After |
3 u |
3x2 =
6 u |
72 |
The number of papayas at first is repeated. Make the number of papayas at first the same. LCM of 10 and 5 is 10.
Total number of fruits left
= 3 u + 6 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Number of fruits at first
= 3 u + 10 u
= 13 u
= 13 x 8
= 104
Answer(s): 104
