Penelope has 3 times as many coins as Irene. Irene has
58 as many coins as Erika. If the three of them have a total of 280 coins, how many coins does Erika have?
| Penelope |
Irene |
Erika |
| 3x5 |
1x5 |
|
| |
5x1 |
8x1 |
| 15 u |
5 u |
8 u |
The number of coins that Irene has is repeated. Make the number of coins that Irene has the same. LCM of 1 and 5 is 5.
Total number of coins that the three of them have
= 15 u + 5 u + 8 u
= 28 u
28 u = 280
1 u = 280 ÷ 28 = 10
Number of coins that Erika has
= 8 u
= 8 x 10
= 80
Answer(s): 80
