Tom and Justin had some beads in the ratio of 12 : 7. Justin and Albert had some beads in the ratio of 2 : 1. Tom sold 170 beads to Albert and ended up with half the number of beads Justin had. How many beads did Albert have in the end?
| Tom |
Justin |
Albert |
| 12x2 |
7x2 |
|
| |
2x7 |
1x7 |
| 24 u |
14 u |
7 u |
The number of beads that Justin had at first is repeated. Make the number of beads that Justin had at first the same. LCM of 7 and 2 is 14.
| |
Tom |
Justin |
Albert |
| Before |
24 u |
14 u |
7 u |
| Change |
- 170 |
|
+ 170 |
| After |
7 u |
14 u |
7 u + 170 |
Number of beads that Tom had in the end
= 14 u ÷ 2
= 7 u
Number of beads that Tom sold to Albert
= 24 u - 7 u
= 17 u
17 u = 170
1 u = 170 ÷ 17 = 10
Number of beads that Albert had in the end
= 7 u + 170
= 7 x 10 + 170
= 70 + 170
= 240
Answer(s): 240
