Warren and Vaidev had some buttons in the ratio of 5 : 4. Vaidev and Rael had some buttons in the ratio of 8 : 7. Warren sold 24 buttons to Rael and ended up with half the number of buttons Vaidev had. How many buttons did Rael have in the end?
| Warren |
Vaidev |
Rael |
| 5x2 |
4x2 |
|
| |
8x1 |
7x1 |
| 10 u |
8 u |
7 u |
The number of buttons that Vaidev had at first is repeated. Make the number of buttons that Vaidev had at first the same. LCM of 4 and 8 is 8.
| |
Warren |
Vaidev |
Rael |
| Before |
10 u |
8 u |
7 u |
| Change |
- 24 |
|
+ 24 |
| After |
4 u |
8 u |
7 u + 24 |
Number of buttons that Warren had in the end
= 8 u ÷ 2
= 4 u
Number of buttons that Warren sold to Rael
= 10 u - 4 u
= 6 u
6 u = 24
1 u = 24 ÷ 6 = 4
Number of buttons that Rael had in the end
= 7 u + 24
= 7 x 4 + 24
= 28 + 24
= 52
Answer(s): 52
