Cole, Seth and Elijah had some marbles. Seth had 40% more marbles than Cole. Seth had ³₅ of Elijah's. After Cole gave 108 marbles to Seth, he had ¹₅ of what Seth had. How many more marbles did Elijah have than Seth in the end?

Cole	Seth	Elijah
5x3	7x3
	3x7	5x7
15	21	35

	Elijah	Cole	Seth	Total marbles of  Cole and Seth
Before	35x1 = 35 u	15x1 = 15 u	21x1 = 21 u	36x1 = 36 u
Change		- 108	+ 108
After	35 u	1x6 = 6 u	5x6 = 30 u	6x6 = 36 u

Number of marbles that Seth had more than Cole at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Cole : Seth = 5 : 7

The number of marbles that Seth had at first is repeated.  Make the number of marbles that Seth had at first the same.  LCM of 7 and 3 is 21.

When Cole gave 108 marbles to Seth, the total number of marbles that Seth and Cole had at first and in the end remains the same.  Make the total number of marbles that Seth and Cole had the same.  LCM of 36 and 6 is 36.

Number of marbles that Cole gave to Seth
= 15 u - 6 u
= 9 u

9 u = 108

1 u = 108 ÷ 9 = 12

Number of marbles that Elijah had more than Seth in the end
= 35 u - 30 u
= 5 u
= 5 x 12
= 60

Answer(s): 60