Neave, Rael and Liam had some marbles. Rael had 80% more marbles than Neave. Rael had
38 of Liam's. After Neave gave 24 marbles to Rael, he had
15 of what Rael had. How many more marbles did Liam have than Rael in the end?
Neave |
Rael |
Liam |
5x1 |
9x1 |
|
|
3x3 |
8x3 |
5 |
9 |
24 |
|
Liam |
Neave |
Rael |
Total marbles of Neave and Rael |
Before |
24x3 = 72 u |
5x3 = 15 u |
9x3 = 27 u |
14x3 = 42 u |
Change |
|
- 24 |
+ 24 |
|
After |
72 u |
1x7 = 7 u |
5x7 = 35 u |
6x7 = 42 u |
Number of marbles that Rael had more than Neave at first in percent
= 100%+ 80%
= 180%
180% =
180100 =
95 Neave : Rael = 5 : 9
The number of marbles that Rael had at first is repeated. Make the number of marbles that Rael had at first the same. LCM of 9 and 3 is 9.
When Neave gave 24 marbles to Rael, the total number of marbles that Rael and Neave had at first and in the end remains the same. Make the total number of marbles that Rael and Neave had the same. LCM of 14 and 6 is 42.
Number of marbles that Neave gave to Rael
= 15 u - 7 u
= 8 u
8 u = 24
1 u = 24 ÷ 8 = 3
Number of marbles that Liam had more than Rael in the end
= 72 u - 35 u
= 37 u
= 37 x 3
= 111
Answer(s): 111