A box contains some mangoes, mangosteens and oranges. 0.2 of the mangoes is equal to 60% of the mangosteens. The number of oranges is ⁵₇ of the total number of mangosteens and mangoes. If there are 65 less mangosteens than oranges, how many fruits are there in the box altogether?

Mangoes	Mangosteens	Oranges
3x7	1x7
7x4		5x4
21 u	7 u	20 u

0.2 = ²₁₀= ¹₅
60% = ⁶⁰₁₀₀ = ³₅

0.2 of the mangoes is equal to 60% of the mangosteens. Make the numerators the same.  LCM of 1 and 3 is 3.

1x35x3 of the mangoes = 3x15x1 of the mangosteens
315 of the mangoes = 35 of the mangosteens 

Mangoes : Mangosteens
15 : 5 _(÷5)
3 : 1

The total number of mangoes and mangosteens is repeated.  Make the total number of mangoes and mangosteens the same.  LCM of 4 and 7 is 28.

Number of less mangosteens than oranges
= 20 u - 7 u
= 13 u

13 u = 65

1 u = 65 ÷ 13 = 5

Number of the fruits in the box altogether
= 21 u + 7 u + 20 u
= 48 u
= 48 x 5
= 240

Answer(s): 240