A box contains some apples, mangoes and chikoos. 0.8 of the apples is equal to 70% of the mangoes. The number of chikoos is
58 of the total number of mangoes and apples. If there are 66 more chikoos than mangoes, how many fruits are there in the box altogether?
Apples |
Mangoes |
Chikoos |
7x8 |
8x8 |
|
8x15 |
5x15 |
56 u |
64 u |
75 u |
0.8 =
810=
45 70% =
70100 =
710 0.8 of the apples is equal to 70% of the mangoes. Make the numerators the same. LCM of 4 and 7 is 28.
4x75x7 of the apples =
7x410x4 of the mangoes
2835 of the apples =
2840 of the mangoes
Apples : Mangoes
35 : 40
(÷5)
7 : 8
The total number of apples and mangoes is repeated. Make the total number of apples and mangoes the same. LCM of 15 and 8 is 120.
Number of more chikoos than mangoes
= 75 u - 64 u
= 11 u
11 u = 66
1 u = 66 ÷ 11 = 6
Number of the fruits in the box altogether
= 56 u + 64 u + 75 u
= 195 u
= 195 x 6
= 1170
Answer(s): 1170