The total volume of water in Tank M, Tank N and Tank P was 283 mℓ. Ian poured out half the volume of water from Tank M, tripled the amount of water in Tank N and poured out 91 mℓ of water from Tank P. The ratio of the volume of water in Tank M to Tank N to Tank P is now 4 : 9 : 5. Find the total volume of water in the three tanks now.
| |
M |
N |
P |
| Before |
8 u |
3 u |
5 u + 91 |
| Change |
- 4 u |
+ 6 u |
- 91 |
| After |
4 u |
9 u |
5 u |
Volume of water in Tank M at first before Julian poured out half the volume
= 2 x 4 u
= 8 u
Volume of water in Tank N at first before Julian tripled the volume
= 9 u ÷ 3
= 3 u
Volume of water in Tank N at first before Julian poured out 91 mℓ of water
= 5 u + 91
Total volume of water in the three tanks at first
= 8 u + 3 u + 5 u + 91
= 16 u + 91
16 u + 91 = 283
16 u = 283 - 91
16 u = 192
1 u = 192 ÷ 16 = 12
Total volume of water in the three tanks now
= 4 u + 9 u + 5 u
= 18 u
= 18 x 12
= 216 mℓ
Answer(s): 216 mℓ
