The total volume of water in Bottle Q, Bottle R and Bottle S was 429 mℓ. Ian poured out half the volume of water from Bottle Q, doubled the amount of water in Bottle R and added 99 mℓ of water into Bottle S. The ratio of the volume of water in Bottle Q to Bottle R to Bottle S is now 9 : 10 : 10. Find the total volume of water in the three bottles now.
| |
Q |
R |
S |
| Before |
18 u |
5 u |
10 u - 99 |
| Change |
- 9 u |
+ 5 u |
+ 99 |
| After |
9 u |
10 u |
10 u |
Volume of water in Bottle Q at first before Luke poured out half the volume
= 2 x 9 u
= 18 u
Volume of water in Bottle R at first before Luke doubled the volume
= 10 u ÷ 2
= 5 u
Volume of water in Bottle R at first before Luke added 99 mℓ of water
= 10 u - 99
Total volume of water in the three bottles at first
= 18 u + 5 u + 10 u - 99
= 33 u - 99
33 u - 99 = 429
33 u = 429 + 99
33 u = 528
1 u = 528 ÷ 33 = 16
Total volume of water in the three bottles now
= 9 u + 10 u + 10 u
= 29 u
= 29 x 16
= 464 mℓ
Answer(s): 464 mℓ
