In a container, there are chocolate bars of 3 colours, red, silver and purple. There are 366 less purple chocolate bars than silver chocolate bars. The number of purple chocolate bars is ²₃ more than the red chocolate bars. Given that the number of purple chocolate bars is 15% of the total number of chocolate bars in the container, how many less red chocolate bars are there than silver chocolate bars?

Red chocolate bars	Silver chocolate bars	Purple chocolate bars
	1 u + 366	1 u
3x3		5x3
85%		15%
9%	76%	15%

1 + ²₃ = ³₃ + ²₃ = ⁵₃

Yellow chocolate bars : Purple chocolate bars = 3 : 5

The number of purple chocolate bars is repeated.  Make the number of purple chocolate bars the same.

5 x 3 = 15%

Total number of red chocolate bars and silver chocolate bars in percent
= 100% - 15%
= 85%

Number of silver chocolate bars in percent
= 85% - 9%
= 76%

Number of more silver chocolate bars than purple chocolate bars in percent
= 76% - 9%
= 61%

61% = 366

1% = 366 ÷ 61 = 6

Number of less red chocolate bars than silver chocolate bars
= 76% - 9%
= 67%
= 67 x 6
= 402

Answer(s): 402