Jean spent $18 on some lemons, chikoos and pomegranates in the ratio of 2 : 3 : 1. The number of lemons was
25 the number of chikoos. The ratio of the number of pomegranates to the number of chikoos was 5 : 3. The lemons were sold at 2 for a dollar.
- How many fruits did she buy altogether?
- How much did each chikoo cost?
Amount spent |
Lemons |
Chikoos |
Pomegranates |
Total |
2 u |
3 u |
1 u |
6 u |
Total amount spent on fruits
= 2 u + 3 u + 1 u
= 6 u
6 u = 18
1 u = 18 ÷ 6 = 3
Amount that Jean spent on lemons
= 2 u
= 2 x 3
= $6
Total number of lemons that Jean bought
= 6 x 2
= 12
Number of fruits bought |
Lemons |
Chikoos |
Pomegranates |
2x3 |
5x3 |
|
|
3x5 |
5x5 |
6 p |
15 p |
25 p |
The number of chikoos bought is repeated. Make the number of chikoos the same. LCM of 3 and 5 is 15.
6 p = 12
1 p = 12 ÷ 6 = 2
Total number of fruits that Jean bought
= 6 p + 15 p + 25 p
= 46 p
= 46 x 2
= 92
(b)
Total number of chikoos that Jean bought
= 15 p
= 15 x 2
= 30
Total amount that Jean paid for the chikoos
= 3 u
= 3 x 3
= $9
Price of each chikoo
= 9 ÷ 30
= $0.30
Answer(s): (a) 92; (b) $0.30