Elijah, Ahmad, Tom and Cody paid a total of $405 for a present. Cody paid
45 of what the rest paid. Elijah paid 25% of what the rest paid. Ahmad and Tom paid an equal amount of money. How much did Tom pay?
| Elijah |
Ahmad |
Tom |
Cody |
Total |
| 5x5 |
4x5 |
9x5 |
| 1x9 |
4x9 |
5x9 |
| |
1 |
1 |
|
|
| 9 u |
8 u |
8 u |
20 u |
45 u |
25%=
25100=
14 Elijah's share : Total share = 1 : 4
The total amount paid for the present is repeated. Make the total amount the same. LCM of 9 and 5 is 45.
Amount that Ahmad, Tom and Cody paid = 36 u
Amount that Ahmad and Tom paid
= 36 u - 20 u
= 16 u
The amount that Ahmad and Tom each paid is the same.
Amount that Ahmad and Tom each paid
= 16 u ÷ 2
= 8 u
Cost of the present = 45 u
45 u = 405
1 u = 405 ÷ 45 = 9
Amount that Tom paid
= 8 u
= 8 x 9
= $72
Answer(s): $72
