There are some students in the fun fair.
110 of them are boys, of whom 70% of them do not wear hats.
49 of the girls do not wear hats. What is the percentage of the students in the fun fair who wear hats?
| Boys |
Girls |
Total |
1x10 =
10 u |
9x10 =
90 u |
10x10 =
100 u |
| No hats |
Hats |
No hats |
Hats |
|
| 7x1 |
3x1 |
4x10 |
5x10 |
|
| 7 u |
3 u |
40 u |
50 u |
100 u |
70% =
70100=
710 The number of boys is the repeated identity. Make the number of boys the same. LCM of 1 and 10 is 10.
Number of students who wear hats
= 3 u + 50 u
= 53 u
Total number of students
= 7 u + 3 u + 40 u + 50 u
= 100 u
Percentage of the students in the fun fair who wear hats
=
53100 x 100%
= 53%
Answer(s): 53%
