The ratio of the number of tarts in Container L to the number of tarts in Container M was 7 : 5. 30% of the tarts in Container L and 0.7 of those in Container M were peach. After transferring the tarts between the 2 containers, the number of mango tarts in both containers are the same. Likewise, the number of peach tarts in both containers are the same. If a total of 288 tarts were moved, how many more tarts were there in Container L than Container M at first?

Container L		Container M
7 u		5 u
Peach	Mango	Peach	Mango
2.1 u	4.9 u	3.5 u	1.5 u
+ 0.7 u	- 1.7 u	- 0.7 u	+ 1.7 u
2.8 u	3.2 u	2.8 u	3.2 u

Number of peach tarts in Container L
= 30% x 7 u
= ³⁰₁₀₀ x 7 u
= 2.1 u

Number of mango tarts in Container L
= 7 u - 2.1 u
= 4.9 u

Number of peach tarts in Container M
= 0.7 x 5 u
= 3.5 u

Number of mango tarts in Container M
= 5 u - 3.5 u
= 1.5 u

Number of peach tarts in each container in the end
= (2.1 u + 3.5 u) ÷ 2
= 5.6 u ÷ 2
= 2.8 u

Number of mango tarts in each container in the end
= (4.9 u + 1.5 u) ÷ 2
= 6.4 u ÷ 2
= 3.2 u

Number of tarts moved
= 0.7 u + 1.7 u
= 2.4 u

2.4 u = 288

1 u = 288 ÷ 2.4 = 120

Number of more tarts in Container L than Container M at first
= 7 u - 5 u
= 2 u
= 2 x 120
= 240

Answer(s): 240