Gwen had some gold buttons and yellow buttons in 2 bags. In Bag N, the ratio of the number of gold buttons to yellow buttons was 8 : 5. In Bag P, the number of gold buttons was 3 times the number of yellow buttons. Gwen transferred
35 of the yellow buttons from Bag N to Bag P. The number of buttons in Bag N became 150 and the ratio of the number of gold buttons to yellow buttons in Bag P became 6 : 7.
- How many yellow buttons were transferred from Bag N to Bag P?
- What was the number of buttons in Bag P after the transfer?
|
Bag N |
Bag P |
|
Gold |
Yellow |
Gold |
Yellow |
Comparing gold buttons and yellow buttons at first |
8 u |
5 u |
3x2 = 6 p |
1x2 = 2 p |
Before |
|
5 u |
|
|
Change |
|
- 3 u |
|
+ 3 u |
After |
|
2 u |
|
|
Comparing gold buttons and yellow buttons in the end |
8 u |
2 u |
6 p |
7 p |
(a)
Total number of buttons in the end for Bag N
= 8 u + 2 u
= 10 u
10 u = 150
1 u = 150 ÷ 10 = 15
Number of yellow buttons that were transferred from Bag N to Bag P
= 3 u
= 3 x 15
= 45
(b)
The number of gold buttons in Bag P remains unchanged. Make the number of gold buttons in Bag P the same. LCM of 3 and 6 is 6.
Increase in the number of yellow buttons in Bag P
= 7 p - 2 p
= 5 p
5 p = 3 u
5 p = 45
1 p = 45 ÷ 5 = 9
Number of buttons in Bag P in the end
= 6 p + 7 p
= 13 p
= 13 x 9
= 117
Answer(s): (a) 45; (b) 117