Ken had to collect some fruits from two marts and deliver some fruits to another mart. He collected from Mart M and the ratio of oranges to chikoos was 5 : 9. When he reached Mart N, he unloaded
1112 of the chikoos and some oranges from his vehicle. The ratio of oranges to chikoos became 2 : 3. At Mart P, 37 oranges and 24 chikoos were collected and the number of oranges to chikoos became the same.
- How many fruits were there on his vehicle after visiting Mart P?
- How many oranges were delivered to Mart N?
|
Location |
Oranges |
Chikoos |
Comparing oranges and chikoos at first |
Mart M |
5x4 = 20 u |
9x4 = 36 u |
Before 1 |
Mart M |
20 u |
12x3 = 36 u |
Change 1 |
Mart N |
- ? |
- 11x3 = - 33 u |
After 1 |
Mart P |
2 u |
1x3 = 3 u |
Before 2 |
Mart P |
2x1 = 2 u |
3x1 = 3 u |
Change 2 |
Mart P |
+ 37 |
+ 24 |
After 2 |
Mart P |
2 u + 37 |
3 u + 24 |
(a)
The number of chikoos after unloading at Mart N is repeated. Make the number of chikoos left after unloading at Mart N the same. LCM of 3 and 1 is 3.
The number of chikoos collected at Mart M is repeated. Make the number of chikoos collected at Mart M the same by multiplying 9 by 4.
The number of oranges and chikoos in the end is the same.
3 u + 24 = 2 u + 37
3 u - 2 u = 37 - 24
1 u = 13
Number of oranges on his vehicle after collecting from Mart P
= 2 u + 37
= 2 x 13 + 37
= 26 + 37
= 63
Number of fruits on his vehicle after collecting from Mart P
= 2 x 63
= 126
(b)
Number of oranges delivered to Mart N
= 20 u - 2 u
= 18 u
= 18 x 13
= 234
Answer(s): (a) 126; (b) 234