Box G and Box H have a total of 70 candy canes. After 6 candy canes were transferred from Box G to Box H, there were 6 times as many candy canes in Box G as Box H. How many candy canes were there in each box at first?
- Box G
- Box H
|
Box G |
Box H |
Total |
Before |
6 u + 6 |
1 u - 6 |
70 |
Change |
- 6 |
+ 6 |
|
After |
6 u |
1 u |
70 |
(a)
The total number of candy canes at first and in the end remains the same.
Total number of candy canes in the end
= 6 u + 1 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of candy canes in Box G at first
= 6 u + 6
= 6 x 10 + 6
= 60 + 6
= 66
(b)
Number of candy canes in Box H at first
= 1 u - 6
= 10 - 6
= 4
Answer(s): (a) 66; (b) 4