Ken, Daniel and Peter have some marbles. The ratios of their marbles are as follows:
Ken : (Ken + Daniel + Peter) = 1 : 4
Daniel : (Ken + Peter) = 1 : 4
Peter has 14 marbles more than Daniel. In the end, Peter gives away all he has to Daniel and Ken so that both Daniel and Ken end up with the same number of marbles, how many marbles has Ken received from Peter?
Daniel |
Peter |
Ken |
Total |
3x5 |
1x5 |
4x5 |
1x4 |
4x4 |
5x4 |
4 u |
11 u |
5 u |
20 u |
The total number of marbles is repeated. Make the total number of marbles the same. LCM of 4 and 5 is 20.
Number of marbles that Peter has more than Daniel
= 11 u - 4 u
= 7 u
7 u = 14
1 u = 14 ÷ 7 = 2
|
Daniel |
Peter |
Ken |
Before |
4 u |
11 u |
5 u |
Change |
+ 6 u |
- 11 u |
+ 5 u |
After |
10 u |
0 u |
10 u |
Number of marbles that Ken has received from Peter
= 10 u - 5 u
= 5 u
= 5 x 2
= 10
Answer(s): 10