Howard, Henry and Oscar have some erasers. The ratios of their erasers are as follows:
Howard : (Howard + Henry + Oscar) = 1 : 4
Henry : (Howard + Oscar) = 1 : 5
Oscar has 35 erasers more than Henry. In the end, Oscar gives away all he has to Henry and Howard so that both Henry and Howard end up with the same number of erasers, how many erasers has Howard received from Oscar?
Henry |
Oscar |
Howard |
Total |
3x3 |
1x3 |
4x3 |
1x2 |
5x2 |
6x2 |
2 u |
7 u |
3 u |
12 u |
The total number of erasers is repeated. Make the total number of erasers the same. LCM of 4 and 6 is 12.
Number of erasers that Oscar has more than Henry
= 7 u - 2 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
|
Henry |
Oscar |
Howard |
Before |
2 u |
7 u |
3 u |
Change |
+ 4 u |
- 7 u |
+ 3 u |
After |
6 u |
0 u |
6 u |
Number of erasers that Howard has received from Oscar
= 6 u - 3 u
= 3 u
= 3 x 7
= 21
Answer(s): 21