Raeann had four containers, F, G, H and J which contained a total of 171 kiwis. She transferred 20 kiwis from Container F to Container G, 42 kiwis from Container G to Container H and 68 kiwis from Container H to Container J. The ratio of the number of kiwis in Container F to Container G to Container H changed from 4 : 5 : 9 to 1 : 2 : 7. How many kiwis were in Container J at first?
| |
Make p the same
(1)x2 = (3) |
F
(1) |
G
(2) |
H
|
J
|
| Before |
8 u |
4 u |
5 u |
9 u |
? |
| Change 1 |
- 40 |
- 20 |
+ 20 |
|
|
| Change 2 |
|
|
- 42 |
+ 42 |
|
| Change 3 |
|
|
|
- 68 |
+ 68 |
| After |
2 p |
1 p |
2 p |
7 p |
? |
4 u - 20 = 1 p --- (1)
5 u + 20 - 42 = 2 p
5 u - 22 =
2 p --- (2)
(1)
x 2 8 u - 40 =
2 p --- (3)
Make p the same.
(3) = (2)
8 u - 40 = 5 u - 22
8 u - 5 u = 40 - 22
3 u = 18
1 u = 18 ÷ 3 = 6
Total number of kiwis in Container F, Container G and Container H
= 4 u + 5 u + 9 u
= 18 u
Total number of kiwis in Container J at first
= 171 - 18 u
= 171 - 18 x 6
= 171 - 108
= 63
Answer(s): 63
