The number of boys to the number of girls in Primary 5 Patience was 2 : 5. The number of boys to the number of girls in Primary 5 Faithfulness was 5 : 6. Both classes had the same number of boys. When 22 girls from Primary 5 Patience joined Primary 5 Faithfulness, the ratio of the number of boys to the number of girls in Primary 5 Patience became 5 : 7. Find the total enrolment of both classes.
Primary 5 Patience |
Primary 5 Faithfulness |
Boys |
Girls |
Boys |
Girls |
2x5 |
5x5 |
5x2 |
6x2 |
1x10 |
|
1x10 |
|
10 u |
25 u |
10 u |
12 u |
The number of boys in both classes is the same. Make the number of boys the same. LCM of 2 and 5 is 10.
|
Primary 5 Patience |
Primary 5 Faithfulness |
|
Boys |
Girls |
Boys |
Girls |
Before |
10 u |
25 u |
10 u |
12 u |
Change |
|
- 22 |
|
+ 22 |
After |
5x2 = 10 u |
7x2 = 14 u |
10 u |
12 u + 22 |
The number of boys in Primary 5 Patience remains unchanged. Make the number of boys in Primary 5 the same. LCM of 10 and 5 is 10.
Number of girls from Primary 5 Patience that joined Primary 5 Faithfulness
= 25 u - 14 u
= 11 u
11 u = 22
1 u = 22 ÷ 11 = 2
Total enrolment of both classes
= 10 u + 25 u + 10 u + 12 u
= 57 u
= 57 x 2
= 114
Answer(s): 114