There were some chikoos and apples in Container C and Container D. In Container C, the ratio of the chikoos to the number of apples was 5 : 1. In Container D, the ratio of the number of chikoos to the number of apples was 3 : 1. There were 3 times as many fruits in Container C as in Container D. After another 55 apples were put into Container D, the ratio of the number of chikoos to the number of apples in Container D became 1 : 4. How many fruits were there in Container D in the end?

Container C		Container D
3x4 = 12 u		1x4 = 4 u
Chikoos	Apples	Chikoos	Apples
5x2	1x2	3	1
10 u	2 u	3 u	1 u

The total number of fruits in Container C is repeated.  Make the total number of fruits in Container C the same.  LCM of 3 and 6 is 12.

The total number of fruits in Container D at first is repeated.  Make the total number of fruits in Container D the same.  LCM of 1 and 4 is 4.

	Container C		Container D
	Chikoos	Apples	Chikoos	Apples
Before	10 u	2 u	3 u	1 u
Change				+ 55
After	10 u	2 u	1x3 = 3 u	4x3 = 12 u

Number of chikoos in Container D remains unchanged.  Make the number of chikoos in Container D the same.  LCM of 3 and 1 is 3.

Number of apples put into Container D
= 12 u - 1 u
= 11 u

11 u = 55

1 u = 55 ÷ 11 = 5

Number of fruits in Container D in the end
= 3 u + 12 u
= 15 u
= 15 x 5
= 75

Answer(s): 75