There were some mangosteens and chikoos in Container J and Container K. In Container J, the ratio of the mangosteens to the number of chikoos was 4 : 1. In Container K, the ratio of the number of mangosteens to the number of chikoos was 3 : 2. There were 3 times as many fruits in Container J as in Container K. After another 20 chikoos were put into Container K, the ratio of the number of mangosteens to the number of chikoos in Container K became 1 : 2. How many fruits were there in Container J?

Container J		Container K
3x5 = 15 u		1x5 = 5 u
Mangosteens	Chikoos	Mangosteens	Chikoos
4x3	1x3	3	2
12 u	3 u	3 u	2 u

The total number of fruits in Container J is repeated.  Make the total number of fruits in Container J the same.  LCM of 3 and 5 is 15.

The total number of fruits in Container K at first is repeated.  Make the total number of fruits in Container K the same.  LCM of 1 and 5 is 5.

	Container J		Container K
	Mangosteens	Chikoos	Mangosteens	Chikoos
Before	12 u	3 u	3 u	2 u
Change				+ 20
After	12 u	3 u	1x3 = 3 u	2x3 = 6 u

Number of mangosteens in Container K remains unchanged.  Make the number of mangosteens in Container K the same.  LCM of 3 and 1 is 3.

Number of chikoos put into Container K
= 6 u - 2 u
= 4 u

4 u = 20

1 u = 20 ÷ 4 = 5

Number of fruits in Container J
= 12 u + 3 u
= 15 u
= 15 x 5
= 75

Answer(s): 75