There were some oranges and persimmons in Container W and Container X. In Container W, the ratio of the oranges to the number of persimmons was 3 : 1. In Container X, the ratio of the number of oranges to the number of persimmons was 3 : 1. There were 3 times as many fruits in Container W as in Container X. After another 64 persimmons were put into Container X, the ratio of the number of oranges to the number of persimmons in Container X became 1 : 3. How many fruits were there in Container W?
Container W |
Container X |
3x4 = 12 u |
1x4 = 4 u |
Oranges |
Persimmons |
Oranges |
Persimmons |
3x3 |
1x3 |
3 |
1 |
9 u |
3 u |
3 u |
1 u |
The total number of fruits in Container W is repeated. Make the total number of fruits in Container W the same. LCM of 3 and 4 is 12.
The total number of fruits in Container X at first is repeated. Make the total number of fruits in Container X the same. LCM of 1 and 4 is 4.
|
Container W |
Container X |
|
Oranges |
Persimmons |
Oranges |
Persimmons |
Before |
9 u |
3 u |
3 u |
1 u |
Change |
|
|
|
+ 64 |
After
|
9 u
|
3 u
|
1x3 = 3 u |
3x3 = 9 u |
Number of oranges in Container X remains unchanged. Make the number of oranges in Container X the same. LCM of 3 and 1 is 3.
Number of persimmons put into Container X
= 9 u - 1 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Number of fruits in Container W
= 9 u + 3 u
= 12 u
= 12 x 8
= 96
Answer(s): 96