Brandon and Dylan were given some allowances each. If Brandon spent $22 each day and Dylan spent $66 each day, Brandon would still have $2873 left when Dylan spent all his allowance. If Brandon spent $66 each day and Dylan spent $22 each day, Brandon would still have $57 left when Dylan spent all his allowance.
- How much allowance did Brandon receive?
- How much allowance did Dylan receive?
|
Case 1 |
Case 2 |
|
Brandon |
Dylan |
Brandon |
Dylan |
Before |
1 u + 2873 |
3 u |
3 p + 57 |
1 p |
Change |
- 1 u |
- 3 u |
- 3 p |
- 1 p |
After |
2873 |
0 |
57 |
0 |
(a)
Simplify the ratio.
22 : 66 = 1 : 3
The allowance that Dylan had at first is the same for Case 1 and Case 2.
1 p = 3 u
3 p = 9 u
The allowance that Brandon had at first is the same for Case 1 and Case 2.
9 u + 57 = 1 u + 2873
9 u - 1 u = 2873 - 57
8 u = 2816
1 u = 2816 ÷ 8 = 352
Allowance that Brandon received
= 1 u + 2873
= 352 + 2873
= $3225
(b)
Allowance that Dylan received
= 3 u
= 3 x 352
= $1056
Answers: (a) $3225; (b) $1056