Oliver was fixing a jigsaw puzzle. By the fifth day, the number of pieces he fixed was 25% of the number of pieces unfixed. After another 3 days, he fixed another 285 pieces and the number of unfixed pieces he was left with was 20% of the number of pieces fixed. How many pieces were left unfixed?
| |
Fixed |
Unfixed |
Total |
| Before |
1x6 =
6 u |
4x6 =
24 u |
5x6 =
30 u |
| Change |
+ 285 |
- 285 |
|
| After |
5x5 =
25 u |
1x5 =
5 u |
6x5 =
30 u |
25% =
25100 =
14 20% =
25100 =
15 Since this is a jigsaw puzzle, there is no change in the total number of jigsaw pieces. Make the total number of jigsaw pieces the same. LCM of 5 and 6 is 30.
Number of additional pieces of jigsaw puzzle that Oliver fixed
= 25 u - 6 u
= 19 u
19 u = 285
1 u = 285 ÷ 19 = 15
Number of pieces that were left unfixed
= 5 u
= 5 x 15
= 75
Answer(s): 75
