Perry has 10% as many beads as Flynn. If Perry gives away 25% of the beads and Flynn gives away 30% of his beads, they will have 279 beads altogether. How many beads do the two of them have?
| |
Perry |
Flynn |
Total |
Comparing Perry
and Flynn at first |
1x4 =
4 u |
10x4 =
40 u |
|
| Before |
4x1 =
4 u |
10x4 =
40 u |
|
| Change |
- 1x1 =
- 1 u |
- 3x4 =
- 12 u |
|
| After |
3x1 =
3 u |
7x4 =
28 u |
279 |
10% =
10100 =
110 25% =
25100 =
14 30% =
30100 =
310 The number of beads that Perry has at first is repeated. Make the number of beads that Perry has the same. LCM of 1 and 4 is 4 u.
The number of beads that Flynn has at first is repeated. Make the number of beads that Flynn has the same. LCM of 10 and 10 is 40 u.
Number of beads in the end
= 3 u + 28 u
= 31 u
31 u = 279
1 u = 279 ÷ 31 = 9
Total number of beads that the two of them have
= 4 u + 40 u
= 44 u
= 44 x 9
= 396
Answer(s): 396
