Xavier has 70% as many stickers as Julian. If Xavier gives away 50% of the stickers and Julian gives away 90% of his stickers, they will have 72 stickers altogether. How many stickers do the two of them have?
|
Xavier |
Julian |
Total |
Comparing Xavier and Julian at first |
7x2 = 14 u |
10x2 = 20 u |
|
Before |
2x7 = 14 u |
10x2 = 20 u |
|
Change |
- 1x7 = - 7 u |
- 9x2 = - 18 u |
|
After |
1x7 = 7 u |
1x2 = 2 u |
72 |
70% =
70100 =
710 50% =
50100 =
12 90% =
90100 =
910 The number of stickers that Xavier has at first is repeated. Make the number of stickers that Xavier has the same. LCM of 7 and 2 is 14 u.
The number of stickers that Julian has at first is repeated. Make the number of stickers that Julian has the same. LCM of 10 and 10 is 20 u.
Number of stickers in the end
= 7 u + 2 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Total number of stickers that the two of them have
= 14 u + 20 u
= 34 u
= 34 x 8
= 272
Answer(s): 272