Jenson's father is 3 times as old as him. His father will be 32 years old in 8 years' time. In how many years' time will Jenson's age be 75% that of his father's?
| |
Jenson's father |
Jenson |
Difference |
Before
(now) |
3x1 =
3 u |
1x1 =
1 u |
2x1 =
2 u |
| Change 1 |
+ 8 |
+ 8 |
|
| After 1 |
32 |
|
|
| Change 2 |
+ ? |
+ ? |
|
| After 2 |
4x2 =
8 u |
3x2 =
6 u |
1x2 =
2 u |
75% =
75100 =
34 Jenson's father : Jenson = 4 : 3
The difference in age between Jenson's father and Jenson always remains the same. Make the difference in age between Jenson's father and Jenson the same. LCM of 2 and 1 is 2.
3 u + 8 = 32
3 u = 32 - 8
3 u = 24
1 u = 24 ÷ 3 = 8
Number of years' time when Jenson's age will be 75% that of his father's
= 8 u - 32
= 8 x 8 - 32
= 64 - 32
= 32
Answer(s): 32
