At a gathering,
13 of the people are children. The remaining group of people is divided into women and men in the ratio of 2 : 5. Each woman is given 4 candies and each man is given 6 candies. Each accompanying child receives 7 candies. Given that only 520 candies are given away to women and children, how many more adults are there than children?
Women |
Men |
Children |
2x7 |
1x7 |
2x2 |
5x2 |
|
4 u |
10 u |
7 u |
The number of adults is repeated. Make the number of adults the same. LCM of 2 and 7 is 14.
|
Women |
Men |
Children |
Number |
4 u |
10 u |
7 u |
Value |
4 |
6 |
7 |
Total value |
16 u |
60 u |
49 u |
Number of candies given away to women and children
= 16 u + 49 u
= 65 u
1 u = 520 ÷ 65 = 8
Number of adults
= 4 u + 10 u
= 14 u
Number of more adults than children
= 14 u - 7 u
= 7 u
= 7 x 8
= 56
Answer(s): 56