Erika had some fruits at her stall.
38 of them were peaches,
14 of the remainder were oranges and the rest were papayas. The amounts earned for each peach, each orange and each papaya sold are $1.40, $1.60 and $1.50 respectively. The number of peaches sold to the number of oranges sold to the number of papayas sold was 3 : 1 : 1. In total, she sold
18 of the fruits and earned $29.20. How many peaches did she have at first?
Peaches |
Oranges |
Papayas |
Total |
3x4 |
5x4 |
8x4 |
|
1x5 |
3x5 |
|
12 p |
5 p |
15 p |
32 p |
The total number of oranges and papayas is repeated. Make the total number of oranges and papayas the same. LCM of 5 and 4 is 20.
|
Peaches |
Oranges |
Papayas |
Number |
3 u |
1 u |
1 u |
Value |
$1.40 |
$1.60 |
$1.50 |
Total value |
4.2 u |
1.6 u |
1.5 u |
Total amount that Erika earned
= 4.2 u + 1.6 u + 1.5 u
= 7.3 u
7.3 u = 29.20
1 u = 29.20 ÷ 7.3 = 4
Total number of fruits sold
= 3 u + 1 u + 1 u
= 5 u
= 5 x 4
= 20
Total number of fruits at first
= 20 ÷
18= 20 x 8
= 160
Total number of fruits at first
= 12 p + 5 p + 15 p
= 32 p
32 p = 160
1 p = 160 ÷ 32 = 5
Number of peaches that Erika had at first
= 12 p
= 12 x 5
= 60
Answer(s): 60