A store owner has 30 more apples than lemons. After he sold 80% of the apples and 10% of the lemons, he is left with 78 more lemons than apples. What fraction of the fruits left were lemons?
| |
Apples |
Lemons |
Comparing apples
and lemons at first |
30 more |
|
| Before |
5x2 =
10 u |
+ 30 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 24 |
- 1x1 =
- 1 u |
| After |
1x2 =
2 u |
+ 6 |
9x1 =
9 u |
Comparing apples
and lemons in the end |
|
78 more |
80% =
80100 =
45 80% x 30 =
45 x 30 = 24
30 - 24 = 6
10% =
10100 =
110 The number of lemons is 78 more than the number of apples in the end. So, if another 78 apples are added, the number of apples and lemons in the end will be the same.
2 u + 6 + 78 = 9 u
2 u + 84 = 9 u
9 u - 2 u = 84
7 u = 84
1 u = 84 ÷ 7 = 12
Number of lemons left
= 9 u
= 9 x 12
= 108
Total number of fruits left
= 2 u + 6 + 9 u
= 11 u + 6
= 11 x 12 + 6
= 132 + 6
= 138
Lemons leftTotal fruits left =
108138 =
1823 Answer(s):
1823 
