A store owner has 60 more apples than persimmons. After he sold 70% of the apples and 40% of the persimmons, he is left with 3 more persimmons than apples. What fraction of the fruits left were persimmons?
|
Apples |
Persimmons |
Comparing apples and persimmons at first |
60 more |
|
Before |
10x1 = 10 u |
+ 60 |
5x2 = 10 u |
Change |
- 7x1 = - 7 u |
- 42 |
- 2x2 = - 4 u |
After |
3x1 = 3 u |
+ 18 |
3x2 = 6 u |
Comparing apples and persimmons in the end |
|
3 more |
70% =
70100 =
710 70% x 60 =
710 x 60 = 42
60 - 42 = 18
40% =
40100 =
25 The number of persimmons is 3 more than the number of apples in the end. So, if another 3 apples are added, the number of apples and persimmons in the end will be the same.
3 u + 18 + 3 = 6 u
3 u + 21 = 6 u
6 u - 3 u = 21
3 u = 21
1 u = 21 ÷ 3 = 7
Number of persimmons left
= 6 u
= 6 x 7
= 42
Total number of fruits left
= 3 u + 18 + 6 u
= 9 u + 18
= 9 x 7 + 18
= 63 + 18
= 81
Persimmons leftTotal fruits left =
4281 =
1427 Answer(s):
1427