A store owner has 50 less persimmons than oranges. After he sold 80% of the persimmons and 35% of the oranges, he is left with 8 less persimmons than oranges. What fraction of the fruits left were persimmons?
|
Persimmons |
Oranges |
Comparing persimmons and oranges at first |
|
50 less |
Before |
5x4 = 20 u |
+ 50 |
20x1 = 20 u |
Change |
- 4x4 = - 16 u |
- 40 |
- 7x1 = - 7 u |
After |
1x4 = 4 u |
+ 10 |
13x1 = 13 u |
Comparing persimmons and oranges in the end |
8 less |
|
80% =
80100 =
45 80% x 50 =
45 x 50 = 40
50 - 40 = 10
35% =
35100 =
720 The number of persimmons is 8 less than the number of oranges in the end. So, if another 8 persimmons are added, the number of persimmons and oranges in the end will be the same.
4 u + 10 + 8 = 13 u
4 u + 18 = 13 u
13 u - 4 u = 18
9 u = 18
1 u = 18 ÷ 9 = 2
Number of persimmons left
= 4 u + 10
= 4 x 2 + 10
= 8 + 10
= 18
Total number of fruits left
= 4 u + 10 + 13 u
= 17 u + 10
= 17 x 2 + 10
= 34 + 10
= 44
Persimmons leftTotal fruits left =
1844 =
922 Answer(s):
922