During a sale, 8 bracelets and 12 rings cost $2004. If Julie bought 15 bracelets and 10 rings, she would have spent all her money. Each bracelet cost $58 more than a ring. Find the amount that Julie had at first.
| |
Case 1 |
Case 2 |
| |
Bracelets |
Rings |
Bracelets |
Rings |
| Number |
8 |
12 |
15 |
10 |
| Value |
1 u + 58 |
1 u |
1 u + 58 |
1 u |
| Total value |
8 u + 464 |
12 u |
15 u + 870 |
10 u |
Cost of 1 ring = 1 u
Cost of 12 rings = 12 u
Cost of 1 bracelet = 1 u + 58
Cost of 8 bracelets = 8 x (1 u + 58) = 8 u + 464
Total cost of 12 rings and 8 bracelets
= 12 u + 8 u + 464
= 20 u + 464
20 u + 464 = 2004
20 u = 2004 - 464
20 u = 1540
1 u = 1540 ÷ 20 = 77
Cost of 15 bracelets = 15(1 u + 58) = 15 u + 870
Cost of 10 rings = 10 u
Amount that Julie had at first
= 15 u + 870 + 10 u
= 25 u + 870
= 25 x 77 + 870
= $2795
Answer(s): $2795
