During a sale, 7 rings and 5 necklaces cost $1672. If Lynn bought 3 rings and 11 necklaces, she would have spent all her money. Each ring cost $148 more than a necklace. Find the amount that Lynn had at first.
| |
Case 1 |
Case 2 |
| |
Rings |
Necklaces |
Rings |
Necklaces |
| Number |
7 |
5 |
3 |
11 |
| Value |
1 u + 148 |
1 u |
1 u + 148 |
1 u |
| Total value |
7 u + 1036 |
5 u |
3 u + 444 |
11 u |
Cost of 1 necklace = 1 u
Cost of 5 necklaces = 5 u
Cost of 1 ring = 1 u + 148
Cost of 7 rings = 7 x (1 u + 148) = 7 u + 1036
Total cost of 5 necklaces and 7 rings
= 5 u + 7 u + 1036
= 12 u + 1036
12 u + 1036 = 1672
12 u = 1672 - 1036
12 u = 636
1 u = 636 ÷ 12 = 53
Cost of 3 rings = 3(1 u + 148) = 3 u + 444
Cost of 11 necklaces = 11 u
Amount that Lynn had at first
= 3 u + 444 + 11 u
= 14 u + 444
= 14 x 53 + 444
= $1186
Answer(s): $1186
